- The shorter a piece of
**wood**is, the more compression it can hold.. Output: Return the side**length**of the largest square that we can have, if not possible function should return 0. ex1: Input: A = 13,**B**= 11. Output: function will return 5 because we can cut**two****sticks****of length**5 from each of the given**sticks**. ex2: Input: Given A = 10,**B**= 21. - Input: A = 13,
**B**= 11 Output: function will return 5 because we can cut**two****sticks****of length**5 from each of the given**sticks**. ex2: Input: Given A = 10,**B**= 21 Output: the function will return 7 because we can split the second**stick****B**into three**sticks****of length**7 and shorten the first**stick**A by 3. ex3: Input: Given A = 2,**B**= 1 - When all the remaining
**sticks**are the same**length**, they cannot be shortened so discard them. Given the**lengths**of**sticks**, print the number of**sticks**that are left before each iteration until**there**are none left. Example. The shortest**stick****length**is , so cut that**length**from the longer**two**and discard the pieces**of length**. Now the**lengths**are ... - Each test case consists of
**two**lines: The first line has an integer n , 1=n=5000, that represents the number of**wooden sticks**in the test case, and the second line contains n**2**positive integers l1, w1, l2, w2, ..., ln, wn, each of magnitude at most 10000 , where li and wi are the length and weight of the i th**wooden stick**,**respectively**. The 2n ... - 32.7. A rectangle has
**two**diagonals. Each one is a line segment drawn between the opposite vertices (corners) of the rectangle. The diagonals have the following properties: The**two**diagonals are congruent (same length ). In the figure above, click 'show both diagonals', then drag the orange dot at any vertex of the rectangle and convince.